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x^2-31x+18=0
a = 1; b = -31; c = +18;
Δ = b2-4ac
Δ = -312-4·1·18
Δ = 889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{889}}{2*1}=\frac{31-\sqrt{889}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{889}}{2*1}=\frac{31+\sqrt{889}}{2} $
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